src/problems/pmch.lisp @ ad32169fc54c
TREE
author |
Steve Losh <steve@stevelosh.com> |
date |
Fri, 20 Dec 2019 16:23:36 -0500 |
parents |
7052ec0c6e1d |
children |
2735aa6aab79 |
(in-package :rosalind)
(defparameter *input-pmch* ">Rosalind_23
AGCUAGUCAU")
(defparameter *output-pmch* "12")
;; We can make a few observations to make things easier (well, trivial).
;;
;; First: the adjacency edges are a red herring. Ignore them.
;;
;; Next: because adenine only interacts with uracil and guanine only interacts
;; with cytosine, we can split the problem apart into two separate graphs. We
;; can compute the number of perfect matchings of each graph separately and then
;; multiply them together at the end to find the total.
;;
;; For each sub graph, every node has edges to all nodes of the complementary
;; base. The problem description also guarantees that the number of
;; complementary bases are equal.
;;
;; Say we're looking at the A/U graph, and there are N adenine bases and
;; N uracil bases. For each adenine, we need to pick a uracil to match it with.
;; For the first adenine we have N uracil's to choose from. For the second
;; adenine we have N-1 uracils. And so on down to the final pair. So the total
;; number of choices we have for each graph is N(N-1)(N-2)…(1) = N!
(define-problem pmch (data stream)
*input-pmch*
*output-pmch*
(let ((bases (nth-value 1 (read-fasta data))))
(* (factorial (count #\A bases))
(factorial (count #\G bases)))))