src/problems/inod.lisp @ 892a16d8007e
TRIE
| author | Steve Losh <steve@stevelosh.com> |
|---|---|
| date | Sat, 18 Jan 2020 14:03:44 -0500 |
| parents | 049e0d632763 |
| children | 2735aa6aab79 |
(in-package :rosalind) ;; This one is trivial once you know the closed-form solution of N-2. The ;; intuition for that can come in two parts. ;; ;; First, a rooted binary tree has N-1 internal nodes. This is because at any ;; given point as you're building the tree, you select 2 of the remaining nodes ;; and join them together with an internal node, which reduces the total ;; remaining by 1. You end when there is only one remaining node (the root) and ;; so you did N-1 subtractions. ;; ;; To convert this to an unrooted tree, you replace the root node with an edge, ;; which subtracts one more internal node from the graph. So you're left with ;; N-2 internal nodes. (define-problem inod (data stream) "4" "2" (- (read data) 2)) #; Scratch -------------------------------------------------------------------- (problem-inod)