ac65fcda590f
Problem 74
author | Steve Losh <steve@stevelosh.com> |
---|---|
date | Mon, 27 Feb 2017 01:15:50 +0000 |
parents | 45b4d825074f |
children | 82da42a326e4 |
branches/tags | (none) |
files | src/euler.lisp |
Changes
--- a/src/euler.lisp Mon Feb 27 00:51:33 2017 +0000 +++ b/src/euler.lisp Mon Feb 27 01:15:50 2017 +0000 @@ -1427,6 +1427,45 @@ (mod <> (expt 10 10)))) + +(defun problem-74 () + ;; The number 145 is well known for the property that the sum of the factorial + ;; of its digits is equal to 145: + ;; + ;; 1! + 4! + 5! = 1 + 24 + 120 = 145 + ;; + ;; Perhaps less well known is 169, in that it produces the longest chain of + ;; numbers that link back to 169; it turns out that there are only three such + ;; loops that exist: + ;; + ;; 169 → 363601 → 1454 → 169 + ;; 871 → 45361 → 871 + ;; 872 → 45362 → 872 + ;; + ;; It is not difficult to prove that EVERY starting number will eventually get + ;; stuck in a loop. For example, + ;; + ;; 69 → 363600 → 1454 → 169 → 363601 (→ 1454) + ;; 78 → 45360 → 871 → 45361 (→ 871) + ;; 540 → 145 (→ 145) + ;; + ;; Starting with 69 produces a chain of five non-repeating terms, but the + ;; longest non-repeating chain with a starting number below one million is + ;; sixty terms. + ;; + ;; How many chains, with a starting number below one million, contain exactly + ;; sixty non-repeating terms? + (labels ((digit-factorial (n) + (sum (mapcar #'factorial (digits n)))) + (term-count (n) + (iterate (for i :initially n :then (digit-factorial i)) + (until (member i prev)) + (collect i :into prev) + (counting t)))) + (iterate (for i :from 1 :below 1000000) + (counting (= 60 (term-count i)))))) + + ;;;; Tests -------------------------------------------------------------------- (def-suite :euler) (in-suite :euler)